Find the area of the vertex triangle using the determinant:(11,8),(3,2),(8,12)
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answer :- 30
Step-by-step explanation:
a (11,8) b (3,2) c (8,12)
area of triangle = 1/2 | x1 (y2-y3) +x2 ( y3-y1 ) + x3 ( y1- y2
Answer : 25
Ok, so lets start
So lets assume
Vertex A of triangle is (11,8)
Vertex B of triangle is (3,2)
Vertex C of triangle is (8,12)
(Just assume vertices are like that).
so, you'll need to use the coordinate geometry formula:
area = | {Ax(By - Cy) + Bx(Cy - Ay) + Cx(Ay - By) }/2 |
Ax and Ay are the x and y coordinates for the vertex of A. The same applies for the x and y notations of the B and C vertices.
remove negative sign form -25.
hence, area = 25.
Or another way is,
Consider the ∆ ABC:
Given in the figure
one by one find the length of sides and calculate area using herons formula. (find the sides using Pythagoras theorem).
as A = (11,8)
B = (3,2)
C = (8,12)
length of AB = √ (| Ax - Bx |)² + (| Ay - By|)²
length of BC = √ (| Bx - Cx |)² + (| By - Cy |)²
length of AC = √ (| Ax - Cx |)² + (| Ay - By |)²
so let's try:
now,
and...
hooray!
same answer 25 using both methods.