Math, asked by diliptalpada265, 9 days ago

Find the area of ​​the vertex triangle using the determinant:(11,8),(3,2),(8,12)
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Answered by nik673260
1

answer :- 30

Step-by-step explanation:

a (11,8) b (3,2) c (8,12)

area of triangle = 1/2 | x1 (y2-y3) +x2 ( y3-y1 ) + x3 ( y1- y2

 \frac{1}{2}

Answered by bhim76
2

Answer : 25

Ok, so lets start

So lets assume

Vertex A of triangle is (11,8)

Vertex B of triangle is (3,2)

Vertex C of triangle is (8,12)

(Just assume vertices are like that).

so, you'll need to use the coordinate geometry formula:

area = | {Ax(By - Cy) + Bx(Cy - Ay) + Cx(Ay - By) }/2 |

Ax and Ay are the x and y coordinates for the vertex of A. The same applies for the x and y notations of the B and C vertices.

      \frac{ 11(2 - 12) + 3(12 - 8) + 8(8 - 2)}{2}

 =    \frac{ - 110 + 12 + 48}{2}

  \frac{ - 50}{2}  =  - 25

remove negative sign form -25.

hence, area = 25.

Or another way is,

Consider the ∆ ABC:

Given in the figure

one by one find the length of sides and calculate area using herons formula. (find the sides using Pythagoras theorem).

as A = (11,8)

B = (3,2)

C = (8,12)

length of AB = √ (| Ax - Bx |)² + (| Ay - By|)²

length of BC = √ (| Bx - Cx |)² + (| By - Cy |)²

length of AC = √ (| Ax - Cx |)² + (| Ay - By |)²

s =  \frac{AB + BC + AC}{2}

area \: =  \sqrt{s(s - a)(s - b)(s - c)}

so let's try:

 AB =  \sqrt{( |11 - 3| )^{2}  + ( |8 - 2| )^{2} } \\  =  \sqrt{{8}^{2}  +  {6}^{2} } \\  =  \sqrt{64 + 36}  \\ =  \sqrt{100}  = 10

BC =  \sqrt{( |3 - 8| )^{2} + ( |2 - 12|) ^{2}   }  \\  =  \sqrt{ {5}^{2} +  {10}^{2}  }  \\   =  \sqrt{25 + 100} \\  =  \sqrt{125}  = 5 \sqrt{5}

AC =  \sqrt{ {( |11 - 8| )}^{2}  +  {( |8 - 12| )}^{2} }  \\  =  \sqrt{ {3}^{2} +  {4}^{2}  }  \\  =  \sqrt{9 + 16}  \\  =  \sqrt{25}  = 5

now,

s =  \frac{10 + 5 \sqrt{5}  + 5}{2}  \\ =  \frac{15+5\sqrt{5}}{2}

Area =  \sqrt{ \frac{ 15+5 \sqrt{ 5  }    }{ 2  }  ( \frac{ 15+5 \sqrt{ 5  }    }{ 2  }  -10)( \frac{ 15+5 \sqrt{ 5  }    }{ 2  }  -5 \sqrt{ 5  }  )( \frac{ 15+5 \sqrt{ 5  }    }{ 2  }  -5) }

 =  \sqrt{625}  = 25

and...

hooray!

same answer 25 using both methods.

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