Question

Find the area of this diagram please!​

Answer 1

Answer:

area of quadrilateral ABCD = 2996.63cm².

Step-by-step explanation:

here, area of Δ ABD + area of Δ BDC = area of quadrilateral ABCD

now, area of Δ ABD = $\sqrt{s (s-a) (s-b) (s-c)}$     where, s = a+b+c/2

                                 = $\sqrt{55 (55-20) (55-20) (55-15)}$

                                 = $\sqrt{55*35*35*40}$

                                 = $\sqrt{2695000}$

                                 = 1641.64cm²

now, area of Δ BCD = $\sqrt{s (s-a) (s-b) (s-c)}$     where, s = a+b+c/2

                                 = $\sqrt{50 (50-20) (50-16) (50-14)}$

                                 = $\sqrt{50*30*34*36}$

                                 = $\sqrt{1836000}$

                                 = 1354.99cm²

∵area of Δ ABD + area of Δ BDC = area of quadrilateral ABCD

 area of quadrilateral ABCD = 1641.64cm² + 1354.99cm²

                                                = 2996.63cm²

hope it will help you.