Find the area of this figure:
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hope u like my process
=====================
Construction:
_____________
=> Joining the gaps
=> making it a rectangle of 11 × 10 cm² Area.
__________________________
Now..
=> Area of figure = Area of rectangle - area of small portions.
So...
Sum of all area of small portions
= (1×2) + (2×2) = 2 + 4 = 6 cm²
=> Area of rectangle = 11×10 =110 cm²
=> Area of figure = 110 - 6 = 104 cm²
________________________
Hope this is ur required answer
Proud to help you
=====================
Construction:
_____________
=> Joining the gaps
=> making it a rectangle of 11 × 10 cm² Area.
__________________________
Now..
=> Area of figure = Area of rectangle - area of small portions.
So...
Sum of all area of small portions
= (1×2) + (2×2) = 2 + 4 = 6 cm²
=> Area of rectangle = 11×10 =110 cm²
=> Area of figure = 110 - 6 = 104 cm²
________________________
Hope this is ur required answer
Proud to help you
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5
1. Area of Rectangle ABCD = l x b = 11 x 10 = 110 sq cm
2. Area of Rectangle XYZW = l x b = 2 x 1 = 2 sq cm
3. Area of Square = side x side = 2 x 2 = 4 sq cm
4. Area of figure = 110 - (2+4)= 110-6 = 104 sq cm
2. Area of Rectangle XYZW = l x b = 2 x 1 = 2 sq cm
3. Area of Square = side x side = 2 x 2 = 4 sq cm
4. Area of figure = 110 - (2+4)= 110-6 = 104 sq cm
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