find the area of this figure
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Answered by
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length of rect. = 2m
breadth of rect. = 1.4m
ar. of rectangle =length × breadth = 2 × 1.4 = 2.8 m²
Diameter of the circle = 1.4m D= radius÷2, r = 0.7 m
Area of a circle = πr²
= (22/7) × (0.7)²
= 1.54 m²
totle ar. of figur = Area of the rectangle + Area of the two semicircles
= 1.54+2.8 = 4.34 m²
breadth of rect. = 1.4m
ar. of rectangle =length × breadth = 2 × 1.4 = 2.8 m²
Diameter of the circle = 1.4m D= radius÷2, r = 0.7 m
Area of a circle = πr²
= (22/7) × (0.7)²
= 1.54 m²
totle ar. of figur = Area of the rectangle + Area of the two semicircles
= 1.54+2.8 = 4.34 m²
Answered by
0
In the given figure, there is a rectangle and two semicircles.
Length of the rectangle(l) = 2m
Breadth of the rectangle(b) = 1.4m
Area of a rectangle = l × b
= 2 × 1.4 = 2.8 m²
There are two semicircles of equal diameter and hence, we can consider them as a single circle.
Diameter of the circle = 1.4m ⇒ radius, r = 0.7 m
Area of a circle = πr²
= (22/7) × (0.7)² (Consider the value of π as 22/7)
= 1.54 m²
Total area of the figure = Area of the rectangle + Area of the circle
= 2.8 + 1.54
= 4.34 m²
Length of the rectangle(l) = 2m
Breadth of the rectangle(b) = 1.4m
Area of a rectangle = l × b
= 2 × 1.4 = 2.8 m²
There are two semicircles of equal diameter and hence, we can consider them as a single circle.
Diameter of the circle = 1.4m ⇒ radius, r = 0.7 m
Area of a circle = πr²
= (22/7) × (0.7)² (Consider the value of π as 22/7)
= 1.54 m²
Total area of the figure = Area of the rectangle + Area of the circle
= 2.8 + 1.54
= 4.34 m²
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