Math, asked by zoyastarfarooqi, 1 year ago

find the area of this figure

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Angella: Do pick the best one out ! :)

Answers

Answered by rjsam
1
 length of rect. = 2m
breadth of rect. = 1.4m
ar. of rectangle =length
× breadth                                                                                                            = 2 × 1.4 = 2.8 m²

Diameter of the circle = 1.4m D= radius÷2, r = 0.7 m
Area of a circle = πr²   
                       = (22/7) × (0.7)²
                       = 1.54 m²

totle ar. of figur = Area of the rectangle + Area of the two semicircles
                                 = 1.54+
2.8                                                                                                                    = 4.34 m²
 








zoyastarfarooqi: ur anser is wrong...
zoyastarfarooqi: the correc anser is 4.34 sq.cm\
rjsam: i thnk this is 3D figure
Angella: That isn't a 3-D figure. Just a rectangle and and two semi-circles.
rjsam: sry figure was not cleared]
RISHABH1515: THIS CORRECT ANSWER IS 4.34 sq. meter
eshansinha015: 4.34msq
Answered by Angella
0
In the given figure, there is a rectangle and two semicircles.
Length of the rectangle(l) = 2m
Breadth of the rectangle(b) = 1.4m
Area of a rectangle = l × b
                            = 2 × 1.4 = 2.8 m²

There are two semicircles of equal diameter and hence, we can consider them as a single circle.
Diameter of the circle = 1.4m ⇒ radius, r = 0.7 m
Area of a circle = πr²   
                       = (22/7) × (0.7)² (Consider the value of π as 22/7)
                       = 1.54 m²

Total area of the figure = Area of the rectangle + Area of the circle
                                 = 2.8 + 1.54
                                 = 4.34 m²
                      

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