Question

Find the area of this figure. Round answer to the nearest hundredth.

Answer 1

Answer:

_______________Topic :- Trigonometry

1) Value of 'cos20° + cos80° - √3.cos50°'.

2) Value of 'cos0° + cosπ/7 + cos2π/7 + cos3π/7 + cos4π/7 + cos5π/7 + cos6π/7'.

3) cos20° + cos40° + cos60° - 4cos10°cos20°cos30°

4) cos20°cos100° + cos100°cos140°+cos140°cos200°

Question from class 9th Trigonometry.

Answer 2

Step-by-step explanation:

hey here is your answer

pls mark it as brainliest

refer the reference diagram uploaded above which contains naming of above figure

so here angle abe=90

so angle abe and angle abc forms a linear pair axiom

thus then angle abc is 90

and moreover then angle bac=90

as both angles bad and angle bac lies on straight line

hence angle bad=90

and angle adc=90 (given)

so in quadrilateral abcd as all angles are 90 degree each

quadrilateral abcd is rectangle

thus then

ab=cd=5 m

bc=ad=6 m

so area of rectangle abcd=l×b

=ab×bc

=6×5

=30 m.square

now in triangle abe

angle abe=90 degrees

hence it is a right angled triangle

so we know that

area of right angled triangle=1/2×product of sides making right angle

thus then

area of triangle abe=1×2×ab×be

=1/2×3×5

=15/2

=7.5 m.square

now considering the given semicircle

here ab represents its diameter which is 6m

hence radius=6/2=3 m

now then we know that

area of semi circle=pi×r square/2

=pi×3×3/2

=pi×9/2

=4.5 pi

substitute value of pi as 22/7

we get

22/7×4.5

=99/7

14.14 m.square

so hence area of given figure=area of rectangle abcd+area of triangle abe+area of semicircle

=30+7.5+14.14

=37.5+14.14

=51.64 m.square

hence area of given figure is 51.64 m.square