Question

find the area of traingle whose sides are...
a=20cm
b=15cm
c=9cm

plz tell correct answer....​

Answer 1

Answer:

▪Let the sides be a,b and c

Area=

$\sqrt{s(s - a)(s - b)(s - c)}$

▪S= semiperimeter =

$\frac{a + b + c}{2} = \frac{20 + 15 + 9}{2} = \frac{44}{2} = 22$

▪Therefore area=

$\sqrt{22(22 -20)(22 - 15)(22 - 9)} = \sqrt{22(2)(7)(13)} = \sqrt{4004} = 63.2 {cm}^{2}$

Area=63.2sq.cm

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Answer 2

Step-by-step explanation:

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