find the area of trapezIum ABCD as given in the figure in which ADCE is a rectangle
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where is figure??
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Answer:
Given: Base = 8cm and Height = 3cm
∴ Thus, the area of ΔBCE = (1/2) x 8 x 3 = 12cm
=> ADCE;
= Area of Rectangle = (l x b)
= ADCE = 8 x 3 = 24cm
=> The area of Trapezium ABCD = Area of ΔBCE + Area of ADCE
= 12 + 24 = 36cm
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