find the area of trapezium BORD in which BO is parallel to DR and BO = 11cm, BD = 6cm, DR = 5cm and RO = 5cm
Vanshu1034:
plz anyone here help me
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Just apply the formula of1/2×sum of parallel sides×height
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Draw RM//BD and RL perpendicular to BO and then we get perpendicular distance=5/12√119 and area =10/3×√119cm^2=36.36
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