Question

Find the area of Trapezium if its height = 7cm and
parallel sides = 8cm and 10cm

Answer 1

Answer❀✿°᭄

Let Z be the number

Z = 13x + 11 where x is the quotient when Z is divided by 13

Z = 17y + 9 where y is the quotient when Z is divided by 17

13x + 11 = 17y + 9

13x + 2 = 17y since x and y are quotients they should be whole numbers . Since y has to be a whole number the left hand side should be multiple of 17

The least possible value of x satisfying the condition is 9 and y will be 7

The answer is 13*9 + 11 = 128 or it is 17*7 + 9 = 128

This is the least number possible. There will be multiple answers and will increase in multiples 17*13 = 221 like 349 , 570, etc

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Answer 2

Step-by-step explanation:

$area \: of \: trapezium \\ = \frac{1}{2} \times (8 + 10) \times 7$

$= \frac{1}{2 } \times 18 \times 7$

$= 9 \times 7$

$area \: is \: 63$