Question

Find the area of trapezium if parallel sides are 12 cm and 10 cm and it's perpendicular height is 8 cm .​

Answer 1

Answer:

$1 \div 2 \times sum \: of \: parallel \: sides \times height$

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Answer 2

Answer:

• Area of the trapezium is 88 cm².

Step-by-step explanation:

Given that:

• Length of 1st parallel side is 12 cm.
• Length of 2nd parallel side is 10 cm.
• Perpendicular height of the trapezium is 8 cm.

To find:

• Area of the trapezium.

Formula Used:

Area of trapezium :

$\sf{\bigg\{\dfrac{1}{2}\times(P_1+P_2)\times H\bigg\}}$

Where,

• P₁ = Length of 1st parallel side
• P₂ = Length of 2nd parallel side
• H = Height

Substituting the values,

$\sf{\bigg\{\dfrac{1}{2}\times(12+10)\times 8\bigg\}\;cm^2}$

Adding 12 and 10 and opening the bracket,

$\sf{\bigg\{\dfrac{1}{2}\times22\times 8\bigg\}\;cm^2}$

Solving further,

$\sf{\bigg\{11\times 8\bigg\}\;cm^2}$

Multiplying 11 and 8,

$\sf{88\; cm^2}$

Hence, area of the trapezium is 88 cm².

More Information:

Properties of trapezium :

• Sum of all the four angles of the trapezium is equal to 360°.
• A trapezium has two parallel sides and two non-parallel sides.
• The diagonals of regular trapezium bisect each other.