Question

Find the area of trapezium PQRS . Given PQ - 10cm PS- 25CM RQ- 16CM Angle QPS - 90°

Answer 1

Answer:

hope it helps bro

Step-by-step explanation:

hmmmhave a good day

Answer 2

Answer:

A=a+b

2h

Step-by-step explanation:

Given : ∠QPS=90 ∠ SQR=90

PQ=12cm , PS=9cm , QR=8cm and SR=17cm

By Pythagoras theorem in ΔSPQ we get :

⇒SP

2

+PQ

2

=SQ

2

⇒9

2

+12

2

=SQ

2

⇒81+144=SQ

2

⇒SQ

2

=225

⇒SQ=

225

​

⇒SQ=15cm

Area of the parallelogram = Area of triangle SPQ + area of triangle SQR.

⇒ Area of Triangle SPQ =  

2

1

​

×base×height

⇒

2

1

​

×PQ×SP

⇒

2

1

​

×12×9

⇒ Area of triangle SPQ = 54cm

2

 

⇒ Area of Triangle SQR =  

2

1

​

×base×height

⇒

2

1

​

×QR×SQ

⇒

2

1

​

×8×15

⇒ Area of triangle SPQ = 60cm

2

 

Total area = area of triangle SPQ + area of trinagle SQR

⇒54+60=114cm

2

Area of quadrilateral PQRS is 114cm

2