Math, asked by ItzSavageGirlIsha, 17 hours ago

Find the area of trapezium where length of parallel sides are 15 cm and 25 cm and the third side measures 12 cm.


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Answers

Answered by muthumanimalothram
31

Answer:

\huge{\bf{\green{\mathfrak{Question:-}}}}

Find the area of trapezium where length of parallel sides are 15 cm and 25 cm and the third side measures 12 cm.

\huge {\bf{\orange{\mathfrak{Answer:-}}}}

Given,

❥ Length of two parallel sides = 15 cm and 25cm

❥ Length of third side (height) = 12 cm

To find:

❥ Area of trapezium

Formulas used:

❥ 1/2 × (Sum of parallel sides) × height

Step by step explaination:

______________________________

→ 1/2 × (15+25)cm × 12cm

→ 1/2 × 40cm × 12cm

→ 240 cm²

______________________________

Therefore, the area of trapezium is 240 cm²

Step-by-step explanation:

I hope it will help you

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Answered by Ʀíɗɗℓεʀ
426

Given :

  • A length of parallel sides are 15 cm and 25 cm and the third side measures 12 cm.

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To Find :

  • Area of trapezium ?

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{\rule{190pt}{2pt}}

SolutioN :

  • Let us assume that, the area of trapezium be x cm.

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{\bf{\dag}} Formula Used :

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\qquad\star~{\underline{\boxed{\pmb{\sf{Area_{(Trapezium)}~=~\dfrac{1}{2}~×~(Sum~of~ Parallel~Sides)~×~ Height}}}}}

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{\bf{\dag}} According to the Question :

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\qquad{\sf:\implies{Area_{(Trapezium)}~=~\dfrac{1}{2}~×~(a~+~b)~×~h}}

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\qquad{\sf:\implies{Area_{(Trapezium)}~=~\dfrac{1}{2}~×~(15~+~25)~×~12}}

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\qquad{\sf:\implies{Area_{(Trapezium)}~=~\dfrac{1}{2}~×~(40)~×~12}}

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\qquad{\sf:\implies{Area_{(Trapezium)}~=~\dfrac{1}{2}~×~480}}

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\qquad{\sf:\implies{Area_{(Trapezium)}~=~\dfrac{1~×~480}{2}}}

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\qquad{\sf:\implies{Area_{(Trapezium)}~=~\cancel\dfrac{480}{2}}}

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\qquad:\implies{\pmb{\underline{\boxed{\pink{\frak{Area_{(Trapezium)}~=~240cm^2 }}}}}}

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Hence,

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\qquad The area of trapezium is 240cm².

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{\rule{190pt}{2pt}}

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