Question

find the area of trapezium whose parallel side are 12 cm and 20 cm and the distance between them is 15 cm​

Answer 1

Answer:

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find the area of trapezium whose parallel side are 12 cm and 20 cm and the distance between them is 15 cm

$\pink{\boxed{\boxed{\boxed{Answer}}}}$

Solve for area

$a \: = \: \frac{a + b}{2} h$

Area of trapezium=

Sum of parallel sides× Height÷2

Area of trapezium:-

12+20/2 X 15

32/2 X 16

11 X 15

= 240 cm^2

Answer 2

Answer:

$\huge \rm \: \: given$

$\sf \: parallel \: side \: of \: trapezium \: = 12 \: and \: 20 cm$

$\sf \: distance \: between \: them \: = 15 \: cm$

$\huge \rm \: to \: find$

$\sf \: area \: of \: trapezium$

$\boxed{ \sf{a \: = \frac{1}{2} \times (sum \: parallel \: side)} \times distance}$

$\sf \dfrac{1}{2} \times (20 + 12) \times 15$

$\sf \: \dfrac{1}{2} \times 32 \times 15$

$\sf \: area \: = 16 \times 15 = 210 \: cm {}^{2}$