Question

Find the area of trapezium whose parallel sides are 10cm and 25cm and non parallel sides are 13cm and 14cm

Answer 1

Answer:

Using Pythagorean theorem and the two right triangles, we can setup 2 equations in 2 unknowns:

h2+x2=132h2+(15−x)2=142⟶⟶h2=169−x2h2=196−(15−x)2

196−(15−x)2=169−x2

196−(225–30x+x2)=169−x2

−29+30x−x2=169−x2

30x=198

x=335

h2=169−x2=169−108925=313625

h=565

Area=b1+b22⋅h=10+252⋅565=196

Step-by-step explanation:

When given a problem like this, it’s always a good idea to draw a diagram.

Drop perpendiculars from shorter base to longer base.

We now have a rectangle with base 10 and height h, and two right triangles with height h, hypotenuse 13 and 14, and bases x and 25–10−x=15−x