Question

find the area of trapezium whose parallel sides are 10m and 16mand perpendicular is 8cm.​

Answer 1

Given 2 parallel side's length 10 m and 16 m

Given Height is 8 cm = 0.08 m

So the area is :-

A=(1/2)(a+b)h

A=(1/2)(10+16)(0.08)

A=(26/2)(0.08)

A=13*0.08

A=1.04 m^2

I hope this helps you and please mark me the brainliest.

Answer 2

Answer:

the area of trapezium ABCD= 104m²

Step-by-step explanation:

let ABCD be a trapezium such that AB=10m, CD=16m and the perpendicular= 8 m

Area of the trapezium=1/2(perpendicular)(AB+CD)

                                    = 1/2*8*(10+16)    

                                    = 4*26=104m²