Question

find the area of trapezium whose parallel sides are 12cmand 20cm and the distance between them is 15cm.​

Answer 1

Given :

• Parallel side is 12 cm and 20 cm
• Distance between them is 15 cm

To find :

• Area of trapezium

Formula used :

• $\star\boxed {\sf\purple{ \frac{1}{2} \times (sum \: of \: parallel \: sides) \times (distance \: between \: them)}}$

According to the formula we will put the value,

$\implies\sf{ \frac{1}{2} \times (12 + 20)cm \times 15 \: cm }$

$\implies\sf{ \frac{1}{ \cancel2} \times \cancel{32 } {}^{ \: \: 16} \: cm \times 15 \: cm}$

$\implies\sf{15 \: cm \times 16 \: cm}$

$\implies\boxed{\sf {240 \: {cm}^{2} }} \green \bigstar$

.°. The area of trapezium is 240 cm²...

Answer 2

Answer:

$\sf \large \star \: { \bold{ \underline{Given :}}} \\ \\ \sf \implies</p><p></p><p>Parallel \: side \: is  \: 12 cm \:  and  \: 20  \: cm \\ \sf \implies</p><p></p><p>Distance \: between \: them \: is  \: 15 cm \\ \\ \sf \large \star \: { \bold{ \underline{To find}}} \\ \\ </p><p> \sf \bullet \: Area \: of \: trapezium \\ \\ </p><p></p><p> \sf \large \star \: { \bold{ \underline{Formula used :}}} \: \ \\ \sf \implies{ \boxed{ \underline{ \bold{area \: of \: trapezium \: = \frac{1}{2} \times \: parallel \: sides \: \times distance}}}}</p><p></p><p> \\ \\ \sf \large \star { \bold{ \underline{solution : }}} \\ \\ \\ \sf \implies \: area \: of \: trapezium \: = \frac{1}{2} \times (12 + 20) \times 15 \\ \\ \sf \implies \: area \: of \: trapezium \: = \cancel \frac{1}{2} \times \cancel {32}^{16} \times 15 \\ \\ \sf \implies \: area \: of \: trapezium \: = 16 \times 15 \\ \\ \sf \implies \: area \: of \: trapezium \: = 240 \: {cm}^{2} \\ \\ \\ \\ \therefore \sf \: { \boxed{ \underline{ \red{ \bold{\sf \implies \: area \: of \: trapezium \: = 240 {cm}^{2}}}}}}$