Question

Find the area of trapezium whose
parallel sides are 15 m&8 m while
height is 12 m​

Answer 1

Answer:

A=138

$a \: base = 15 \\ b \: base = 8 \\ h \: height = 12 \\ \\ \\ a = \frac{a + b}{2} h \\ \\ \\ = \frac{15 + 12}{2} .12 \\ \\ \\ = 138$

Hope this helps

Answer 2

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A=138

$\begin{gathered}a \: base = 15 \\ b \: base = 8 \\ h \: height = 12 \\ \\ \\ a = \frac{a + b}{2} h \\ \\ \\ = \frac{15 + 12}{2} .12 \\ \\ \\ = 138\end{gathered}$

$a \: base=15b \: base=8h \: height=12a=2a+bh=215+12.12=138$

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