Find the area of trapezium whose parallel sides are 1m and 1.2 m and perpendicular distance between them is 0.8 m.
Answers
Answer:
0.88 m²
Step-by-step explanation:
\mathtt{\purple{ \huge \underline{\fbox{ \: \green{ Solution \red : \: \: }}}}}
Solution :
Given ,
The parallel sides of trapezium are 1 m and 1.2 m
The perpendicular distance between them is 0.8 m
We know that , the area of trapezium is given by
\mathtt{ \large \purple{ \underline{ \fbox{ \green{Area \: of \: trapezium = \frac{1}{2} (sum \: of \: parallel \: sides)(height)}}}}}
Substitute the values , we obtain
\begin{gathered} \sf \hookrightarrow Area = \frac{1}{2} (1 + 1.2) \times (0.8) \\ \\ \sf \hookrightarrow Area = \frac{1}{2}( 2.2) \times (0.8) \\ \\ \sf \hookrightarrow Area = \frac{22}{20} \times \frac{8}{10} \\ \\ \sf \hookrightarrow Area = \frac{176}{200} \\ \\ \sf \hookrightarrow Area = 0.88 \: \: {m}^{2} \end{gathered}
↪Area=
2
1
(1+1.2)×(0.8)
↪Area=
2
1
(2.2)×(0.8)
↪Area=
20
22
×
10
8
↪Area=
200
176
↪Area=0.88m
2
Hence , the area of trapezium is 0.88 m²
★ Given :–
⇝ Parallel sides = 1m and 1.2m
⇝ Perpendicular dist. between them = 0.8m
★ Formula :–
↬ Area of Trapezium = ½ × Sum of parallel sides × distance between them.
★ Solution :–
~ Therefore, Area of the Trapezium is 0.88m²