Question

Find the area of trapezium whose parallel sides are 20cm and 18cm long, and the distance between them is 15cm.

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Answer 1

Answer :

›»› The area of trapezium is 285 cm².

Given :

• The parallel sides of a trapezium is 20 cm and 18 cm long.
• Distance between them is 15 cm.

To Find :

• The area of trapezium = ?

Solution :

As we know that

→ Area of trapezium = 1/2 * (sum of parallel sides) * height.

→ Area of trapezium = 1/2 * (a + b) * h

→ Area of trapezium = 1/2 * (20 + 18) * 15

→ Area of trapezium = 1/2 * 38 * 15

→ Area of trapezium = 1 * 19 * 15

→ Area of trapezium = 19 * 15

→ Area of trapezium = 285

Hence, the area of a trapezium is 285 cm².

Extra Brainly Knowledge :

❒ A trapezium is also a quadrilateral, which is defined shape with four unequal sides and two non-parallel sides.

❒ There are some more examples of trapezium or quadrilateral.

• Rectangle.
• Square.
• Rhombus.
• Parallelogram.

❒ The sum of all four angles of a trapezium or a quadrilateral is 360°. This statement is call angle sum property of a trapezium or a quadrilateral.

Formula of trapezium :

• Area = 1/2 * (sum of parallel sides) * height.
• Perimeter = Sum of all sides.

Answer 2

♣GIVEN♣

• Parallel sides of the trapezium = 20 cm and 18 cm

• Distance between the sides = height = 15 cm

♣TO FIND♣

• Area of the trapezium

♣SOLUTION♣

• We Have To Find The Area Using The Formula Of Finding Area Of A Trapezium :-

$\huge {\boxed{ \boxed{ \bf{ \mapsto{Area = \dfrac{1}{2}× \huge{\bigg(}Sum~of~the~Parallel~sides×Height }}}}}$

★══════════════════════★

❐ Putting all values :-

$➱ \: \frak{Area = \dfrac{1}{2} \times \bigg(20 + 18 \bigg) \times 15 }$

$➱ \: \frak{Area = \dfrac{1}{2} \times 38 \times 15}$

$➱ \: \frak{Area = \dfrac{1}{ \cancel2 \large{_ 1}} \times \cancel{570 } ^{\large{{285}}}}$

$➱ \: {\underline{\boxed{\frak{Area = 285 \: {cm}^{2} }}}}$

♣ANSWER♣

• The area of the trapezium is 285 cm²