Question

Find the area of trapezium whose parallel sides are 24cm and20cm and the distance between them is15cm

Answer 1

GIVEN:

• Parallel sides of trapezium are 24 cm and 20 cm
• Distance between them = Height = 15 cm

TO FIND:

• What is the area of trapezium ?

SOLUTION:

We know that the formula for finding the area of trapezium is:-

$\bf{\star \: Area = \dfrac{1}{2} \times (sum \: of \: parallel \: sides) \times height \: \star}$

According to question:-

On putting the values in the formula, we get

$\rm{\dashrightarrow Area = \dfrac{1}{2} \times (24 + 20) \times 15}$

$\rm{\dashrightarrow Area = \dfrac{1}{\cancel{2}} \times \cancel{44} \times 15}$

$\rm{\dashrightarrow Area = 22 \times 15}$

$\bf{\star \: Area = 330 \: cm^2\: \star}$

❝ Hence, the area of the trapezium is 330 cm² ❞

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✮ Extra Information ✮

➱ The midline of a trapezium is parallel to the bases.

➱ The length of the midline of a trapezium is one half the sum of the lengths of the bases.

Answer 2

✯✯ QUESTION ✯✯

Find the area of trapezium whose parallel sides are 24cm and 20cm and the distance between them is 15cm..

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✰✰ ANSWER ✰✰

$\implies\tt{Sum\:of\:parallel\:sides=24cm\:and\:20cm}$

$\implies\tt{Height(h)=15cm}$

➥Using Formula : -

$\implies\tt{Area\:of\:Trapezium=\dfrac{1}{2}\times{(Sum\:of\:parallel\:sides)}\times{height}}$

➥Putting Values : -

$\implies\tt{\dfrac{1}{2}\times{(24+20)}\times{15}}$

$\implies\tt{\dfrac{1}{\cancel{2}}\times{\cancel{44}}\times{15}}$

$\implies\tt{22\times{15}}$

$\implies\tt{\large{\boxed{\bold{\bold{\red{\sf{{330cm}^{2}}}}}}}}$

☛So , Area of Trapezium is 330cm²..

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✔Properties of Trapezium : -

★Sum of angles of a trapezium is 360°..

★Diagonals of Trapezium bisects each other..

★Pair of opposite sides are non-parallel..

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