Question

find the area of trapezium whose parallel sides are 24cm and the distance between them is 15cm​

Answer 1

Answer:

1]area of trapezium = 1/2 * distance between two parallel sides * ( sum of two parallel sides)

therefore here

area = 1/2 * 15 * (24+20)

= 1/2 * 15 * 44

= 22 *15

330 sqcm

2]given the Length one of the parallel side of the trapezium is 38.7cm and and the other parallel side is 22.3cm.

given height is 16cm.

area of the trapezium = 1/2×h(b1+b2)

= 1/2×16(38.7+22.3)

= 8×61

= 488cm²

3] Area of a trapezium= (1/2*sum of parallel sides*height)

Let the distance between them be x

1080cm^2= (1/2*(34.4cm+55.6cm)*x)

x= 12cm

Ans= 12cm

4] area of trapezium = 1586 cm²

(1/2) × (sum of parallel sides) × height = 1586 cm²

1/2 × (84+other side) × 26 = 1586 cm²

84+other side = (1586×2)/26

84+other side = 112

other side = 122-84 = 38 cm

5] height of trapezium =9 cm

one of other side of trapezium is longer than 6 cm

one is 6cm and other is x+6

Area of trapezium =

1÷2 (sum of parallel sides )×height

1÷2 ( x + x+6) ×9 =180

1÷2 (2x+6)×9= 180

x+3×9=180

x+3=180÷9

x+3=20

x=20-3

x=17

one side is x = 17 cm

other side x+6 =17+6=23cm

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Step-by-step explanation:

Answer 2

ANSWER

We know,

Area of trapezium= 2/1×Sum of parallel sides×Distance between them.

Area of trapezium = 2/h(a+b), where a and b are base and h is height.

Here, a=24 cm, b=20 cm and h=15 cm

Therefore, Area= 2/15(24+20)=330cm