Question

find the area of trapezium whose parallel sides are 36 cm and 42 cm and the distance between them 18cm​

Answer 1

Answer:

802cm^2

Step-by-step explanation:

1/2×(b1+b2)×h

1/2×78×18

78×9

802cm^2

Answer 2

Answer

702cm^2

Step-wise explanation

Given,

Parallel sides=36cm, 42cm

Therefore,

sum of parallel sides=(36+42) cm

=78cm

Distance between them=18cm

We know,

Area of trapezium =

$( sum \: ofparallel \: sides \times distance \: between \: them) \div 2$

=

$(78cm \times 18cm) \div 2$

$(1404 cm^2 ) \div 2$

$702 {cm}^{2} (ans)$