find the area of trapezium whose parallel sides are 4 cm and 7 cm and distance between parallel lines is 5 cm
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Answer:
1/2×(7+4)×5
=1/2×55
27.5
Step-by-step explanation:
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☆ Solution ☆
Given :-
- Parallel sides of trapezium are 4 cm and 7 cm.
- Distance between parallel lines is 5 cm.
To Find :-
- The area of trapezium.
Step-by-Step-Explaination :-
As we know that :-
Area of trapezium = 1/2 × ( sum of parallel sides ) × distance between them
Putting the respective value,
Area of trapezium = 1/2 × ( 4 + 7 ) × 5
Area of trapezium = 1/2 × 11 × 5
Area of trapezium = 5.5 × 5
Area of trapezium = 27.5
Hence,
Area of trapezium = 27.5 cm²
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Know More :-
Perimeter of Rectangle = 2 ( l + b )
Perimeter of Square = 4 × side
Perimeter of Triangle = 3 × side
Area of Rectangle = L × B
Area of Square = ( side ) ²
Area of Rhombus = Product of Diagonal/2.
Area of Parallelogram = Base × Height.
Area of triangle = 1/2 × base × height
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