Math, asked by kumarashwani5605, 5 months ago

find the area of trapezium whose parallel sides are 42 cm and 38 cm and distance between them is 15cm.​

Answers

Answered by suyash638
0

Answer:

area of trapezium=1/2× sum of parallel side×distance between them

=1/2×(42+38)×15

=1/2×80×15=600cm²

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Answered by srhandsome
0

Step-by-step explanation:

Let 'a' and 'b' be the parallel sides of the trapezium, i.e,

a = 42 cm

b= 38 cm

Let 'h' be the height, i.e, perpendicular distance between the parallel sides = 15 cm

Area of the given trapezium = 1/2 h (a + b)

= 1/2 × 15 × ( 42 +38 )

= 1 /2 × 15 × 80

= 600 cm ^2

Hope it helped.

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