find the area of trapezium whose parallel sides are 42 cm and 38 cm and distance between them is 15cm.
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Answer:
area of trapezium=1/2× sum of parallel side×distance between them
=1/2×(42+38)×15
=1/2×80×15=600cm²
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Step-by-step explanation:
Let 'a' and 'b' be the parallel sides of the trapezium, i.e,
a = 42 cm
b= 38 cm
Let 'h' be the height, i.e, perpendicular distance between the parallel sides = 15 cm
Area of the given trapezium = 1/2 h (a + b)
= 1/2 × 15 × ( 42 +38 )
= 1 /2 × 15 × 80
= 600 cm ^2
Hope it helped.
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