Find the area of trapezium whose parallel sides are 48 m and 160m and non parallel sides are 50m and 78 m
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let a and b are are the non parallel sides
c and d are parallel sides
therefore,a=160m (a>b)
b=48m
c=50m
d=78m
k=a-b
k=160-48
k=112
s=(c+d+k)/2=(50+78+112)/2=240/2
s=120
area of trap= (a+b)/k sqr root(s(s-c)(s-d)(s-k))
=(160+48)/112
(120(120-50)(120-78)(120-112))
=208÷112 sqr rt(120×70×42×8)
=208/112 ×1680
=208×15
=3120
therefore area of trapezium =3120m^2
c and d are parallel sides
therefore,a=160m (a>b)
b=48m
c=50m
d=78m
k=a-b
k=160-48
k=112
s=(c+d+k)/2=(50+78+112)/2=240/2
s=120
area of trap= (a+b)/k sqr root(s(s-c)(s-d)(s-k))
=(160+48)/112
(120(120-50)(120-78)(120-112))
=208÷112 sqr rt(120×70×42×8)
=208/112 ×1680
=208×15
=3120
therefore area of trapezium =3120m^2
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