Question

find the area of trapezium whose parallel sides are 57 cm and 33 cm and the distance between then is 13

Answer 1

Area of Trapezium= 1/2 x (sum of the parallel sides) x distance between them
                             = 1/2 x (57+33) x 13
                             =1/2 x 90 x 13
                             =1 x 45 x 13 ( on simplifying 2 and 90)
                             = 585sq. cm

Answer 2

hello vivek

$\huge\bold \green{solution}$

$\frac{1}{2} \times (57cm + 33cm) \times 13cm$

$\frac{90cm}{2} \times 13 cm$

$45cm \times 13cm$

$585 {cm}^{2}$