Find the area of trapezium whose parallel sides are 9cm and 15cm and the distance between them is 8cm.
Answers
Answered by
4
heya frnd!
here's ur answer...
given:-
b1=9cm
b2=15cm
height of the trapezium=8cm
therefore area of the trapezium=1/2×h(b1+b2)
=1/2×8(9+15)
=4×24
=96cm²
hence, the area of the trapezium is 95cm².
hope this helps...
^_^
here's ur answer...
given:-
b1=9cm
b2=15cm
height of the trapezium=8cm
therefore area of the trapezium=1/2×h(b1+b2)
=1/2×8(9+15)
=4×24
=96cm²
hence, the area of the trapezium is 95cm².
hope this helps...
^_^
Answered by
2
Heya friend,
Given that
Ist parallel side = 9 cm
2nd parallel side = 15 cm
Distance between them = 8 cm
Solution
Area of a trapezium = 1/2 × sum of parallel sides × distance between them
= 1/2 (9 + 15) × 8
= 4 × 24
= 96 cm^2
Thanks
With regards@
Tanisha
Given that
Ist parallel side = 9 cm
2nd parallel side = 15 cm
Distance between them = 8 cm
Solution
Area of a trapezium = 1/2 × sum of parallel sides × distance between them
= 1/2 (9 + 15) × 8
= 4 × 24
= 96 cm^2
Thanks
With regards@
Tanisha
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