Find the area of trapezium whose parallel sides are of length 3cm and 9cm, and the distance between the two parallel sides is 2.5cm
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Answered by
1
Answer:
Given: Length of parallel sides are 9cm and 5cm
Height =8cm
Area of trapezium=
2
1
× Height ×(Sum of parallel sides)
=
2
1
×8cm×(9+5)cm
=
2
8+14
cm
2
=56cm
2
.
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Answered by
3
Answer :-
- Area of the Trapezium, a = 15 cm²
Explanation :-
Given :-
- Parallel side of the Trapezium, p₁ = 3 cm
- Parallel side of the Trapezium, p₁ = 9 cm
- Distance between the two parallel side (i.e, p₁ and p₂), h = 2.5 cm
To find :-
- Area of the Trapezium, a = ?
Knowledge required :-
Formula for area of a Trapezium :
⠀⠀⠀⠀⠀⠀A = ½ × (p₁ + p₂) × h⠀
[Where : A = Area of the Trapezium, p₁ and p₂ are the two parallel sides of the Trapezium and h is the distance between the two parallel sides]
Solution :-
By using the formula for area of a Trapezium and substituting the values in it, we get :
- ⠀⠀=> A = ½ × (p₁ + p₂) × h
- ⠀⠀=> A = ½ × (3 + 9) × 2.5
- ⠀⠀=> A = ½ × 12 × 2.5
- ⠀⠀=> A = 6 × 2.5
- ⠀⠀=> A = 15
⠀⠀∴ A = 15 cm²
Hence, the area of the Trapezium is 15 cm².
_________✰___________
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