Question

find the area of trapezium with base15 cm and height 8cm if the side parallel to the given base is 9cm long

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Answer 1

Answer:

A=1/2*(a+b)*h

=1/2*(15+9)*8

=24*4

=96cm^2

=0.96m^2

Answer 2

Given =

Base of trapezium :- (base 1) = 15 cm

Base of trapezium :- (base 2) = 9 cm

Height of trapezium (h) = 8 cm

Area of Trapezium =

$\frac{1}{2}$ × base 1 + base 2 × h

$\frac{1}{2} \times \: (15 + 9) \: \times \: 8$

$\frac{1}{2} \: \times \: 24 \times 8$

$Answer :- \: 96 \: {cm}^{2}$