Question

Find the area of trapezium with the dimensions:
sum of parallel sides = 12cm, height = 4.5cm.​

Answer 1

$\sf{area \: of \: trapazium = \frac{1}{2} \times (sum \: of \: parallel \: sides) \times height}$

$= > \: \: \: \: \: \: \: \: \: \frac{1}{ \cancel{2}} \times \cancel{12} \times (4.5)$

$\: \: \: \: \: = > \sf { \: \: \: \: \: \: \: \: 6 \times 4.5}$

$\: \: \: \: \: \: \: \: \: = > \: \: \: \: \: \sf{ 27 {cm}^{2}}$