Question

find the area of trapizum whose prallel sides are 12 cm and 20 cm and the distance between them is 15 cm

Answer 1

Answer: 240 c$m^{2}$

Step-by-step explanation:

Area of trapezium = $\frac{1}{2} .(sum of parallel side)(dist. b/w them )$

                             =$\frac{1}{2}.(12+20).15$

                             = $\frac{1}{2}.32.15=16X15$

                             = 240 c$m^{2}$

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Answer 2

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