Find the area of triangle 10cm , 10cm , 8cm
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Solution
Given :-
- Length of side of triangle , 10 cm , 10 cm , 8 cm
Find :-
- Area of triangle
Explanation
Let,
A triangle be ∆ABC .
Where,
- AB = 10 cm
- BC = 10cm
- CA = 8 cm
Using Formula
★ Semi perimeter ( S) = (AB + BC + CA)/2
★ Area = √[S(S-AB)(S-BC)(S-CA)]
First Calculate, Semi perimeter.
==> S = (10 + 10 + 8)/2
==> S = 28/2
==> S = 14 cm
Now, calculate area,
==> Area = √[S(S-AB)(S-BC)(S-CA)]
Keep all above Values,
==> Area = √[14 (14 - 10)(14 - 10)(14 - 8)]
==> Area = √[ 14 × 4 × 4 × 6]
==> Aea = √( 2 × 2 × 2 × 2 × 2 × 2 × 7 × 3)
==> Area = (2×2×2)√21
==> Area = 8√21 cm²
Hence
- Area will be of given triangle ∆ABC = 8√21 cm²
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