find the area of triangle (5,-2)(6,4)(7,-2)
please it is urjent
Answers
Answer:
A=hbb
2
Step-by-step explanation:
Let ABC be the triangle A(5,−2),B(6,4),C(7,−2)
By distance formula
AB=
(5−6)
2
+(−2−4)
2
=
(−1)
2
+(−6)
2
37
BC=
(6−7)
2
+(4−(−2)
2
=
(−1)
2
+(6)
2
=
37
CA=
(7−5)
2
+(−2−(−2))
2
=
(2)
2
+0
=2
Since AB=BC=
37
Hence (5,−2),(6,4) & (7,−2) are vertices of isosceles triangle.
Answer:
x1=5, x2=6, x3=7
y1= - 2,y2=4, y3=-2
Area of triangle =Absolute value of
x1(y2-y3) + x2(y3-y1) + x3(y1-y2) ÷ 2
=5(4 - (-2)) + 6(-2-(-2)) + 7(-2-4) ÷2
=5(6) + 6(0) + 7(-6) ÷2
=30 + 0 - 42 ÷2
=30-42 ÷2 = - 12 ÷2 = - 6
Removing the negative sign since the formula calls for absolute value, area of triangle is equal to 6.
Formula is the key. Just remember the formula to be able to find out area of any triangle when vertices are given.