Find the area of triangle AB = 13m , BC = 8cm angle BAC= 45⁰ , Angle BCA= 45⁰
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by angle sum property <ABC=90°
∆ABC is right angled at B
therefore in ∆ABC
AB is the height=13cm and
BC Is base=8 cm
area of ∆= 1/2(bh)
=1/2*(8*13)
= 104/2
=52cmsq
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