Question

find the area of triangle ab=ac=13 bc=10​

Answer 1

To find :

area of the triangle ABC

Given :

AB = AC = 13

BC = 10

Formula to be used :

• Area of triangle (heron's Formula )

$\sqrt{s(s - a)(s - b)(s - c)}$

where, s is the semi perimeter of the triangle

Solution:

semi perimeter = (10+13+13)/2

= (36)/2

= 18

so, area of the triangle:

$\sqrt{s(s - a)(s - b)(s - c)} \\ = \sqrt{18(18 - 13)(18 - 13) (18 - 10)} \\ = \sqrt{18 \times 5 \times 5 \times 8} \\ = 5 \sqrt{2 \times 3 \times 3 \times 2 \times 2 \times 2} \\ = 5 \times 2 \times 2 \times 3 \\ = 60$

so, area of the triangle = 60