find the area of triangle ABC given that AB =BC =8cm, ANGLE ABC =90 DEGREE
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Answered by
53
area of triangle = 1/2*AB* BC
= 1/2*8*8
=4*8
=32cm²
= 1/2*8*8
=4*8
=32cm²
Answered by
47
In ∆ ABC :- Angle ABC = 90° and AB = BC = 8cm
Therefore, area of ∆ ABC = ½ × 8 × 8 = 32 cm²
Hope this helps.....
Therefore, area of ∆ ABC = ½ × 8 × 8 = 32 cm²
Hope this helps.....
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