find the area of triangle ABC given that CA = 7cm angle ABC = angle BCA = 45 °
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Thank you for asking this question. Here is your answer:
Since the triangle is isosceles, we have BA = CA = 7 cm.
m∠BAC = 180° - m∠ABC - m∠CBA
= (180-45-45)°
= 90°,
so BA and CA are perpendicular.
Therefore the area of the triangle is
(1/2) BA * CA
= 24.5 cm^2.
If there is any confusion please leave a comment below.
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