find the area of triangle ABC if angle A is equal to 60 degree,angle b is equal to 30 degree and c b is equal to 6 cm
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Answer:
Step-by-step explanation:
Clearly it's a right angled triangle.hence tan b =AC/BC.so AC =2√3.hence area =1/2×2√3×6=6√3
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Step-by-step explanation:
angle A is 60
angle B is 30
so , angle C should be 90 ( using angle sum prop. )
that means triangle is a right angled triangle...
therefore tan30 = AC / BC
1/√3 = AC / 6
AC = 6/√3
area of triangle = 1/2 * base * height
base = 6cm
height we found = 6/√3
therefore area = 1/2 * 6*6/√3 = 18/√3 cm^2
or Area = 6√3 cm^2
thank u...
hope it helps :)
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