Question

Find the area of triangle ABC (in sq. units) whose vertices are A(1,3),B(-1,0) and C(4,0)?

Answer 1

1/2(1(0-0) + -1(0-3) + 4(3-0)

1/2 (0+3+12)

15/2

Answer 2

Answer:7.5 units square

Step-by-step explanation:

Area of a triangle is given by the equation,

A =

2

1

​

[x

1

​

(y

2

​

−y

3

​

)+x

2

​

(y

3

​

−y

1

​

)+x

3

​

(y

1

​

−y

2

​

)]

here the given points are A(1,3),B(-1,0) and C(4,0)

by Substituting ,

A =

2

1

​

[1(0−0)+(−1)(0−3)+4(3−0)]

=

2

1

​

[3+12]=

2

15

​

=7.5