Find the area of triangle ABC in which ab = ac = 4 cm and angle a = 90 0 ????
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as per prob
ab=ac=4cm
angle =90 °
so ab becomes the altitude
ac becomes the base
1/2(base)(altitude)
= 1/2(4)(4)
=8
ans = 8 cm
ab=ac=4cm
angle =90 °
so ab becomes the altitude
ac becomes the base
1/2(base)(altitude)
= 1/2(4)(4)
=8
ans = 8 cm
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