Question

find the area of triangle ABC in which an =4cm bc =5cm and angle a=90 degree

Answer 1

In  Triangle ABC

<A=90

So, By Pyathagora Theorem,

AB^2+AC^2=BC^2

=>(4)^2+AC^2=(5)^2

=>16+AC^2=25

=>AC=3cm

We know  that the area of a triangle is equal to 1/2*perpendicular*base

=>Area of ABC = 1/2*4*3

=2*3=6 cm^2

Thanks!!!