Math, asked by aden7433, 11 months ago

Find the area of triangle abc in which bc=8cm,ac=15cm and ab=17cm .Find the length of altitude drawn on ab

Answers

Answered by sumersinghsodha155n
2

Answer:

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Answered by kanikacutechauhan
4

Answer:

AREA = 60 CM

ALTITUDE = 15 CM

                 

Step-by-step explanation:

AB = 17 CM

BC = 8 CM

AC = 15 CM

PERIMETER = AB +BC+AC

                    = 17+8+15

                   = 40CM

SEMI PERIMETER =40/2

                            = 20CM

AREA OF TRIANGLE = √S (S-AB) (S-BC) (S-AC)

                                  = √20 (20-17) (20-8) (20-15)

                                  =√ 20 *3*12*5

                                 = √2*2*5*3*3*2*2*5

                                  =2*2*3*5

                                 = 60 CM

AREA OF TRIANGLE = 1/2 *B *H

                         60      = 1/2 * 8 *H

                          60      = 4H

                          H       =  60/4

                           H       15CM

ALTITUDE =15 CM

                                   

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