Question

Find the area of triangle abc ,right angled at b in which ab =24cm and bc=10cm.

Answer 1

ABC is right angle triangle therefore

by Pythagoras theorem:-

AB²+BC²=AC²

ΑΒ²=AC²−BC²

ΑΒ²=(24)²−(10)²

ΑΒ²=(24–10)(24+10)

AB²=16*36

AB=√16×36

ΑΒ=4×6

ΑΒ=24cm

Answer 2

To find: Area of a Right-angled triangle

AB =perpendicular

BC=base

And, AC=hypotenuse

Area of triangle = 1/2 * perpendicular *base

Area of the triangle= 1/2* 24*10 metre square

Area if triangle = 120 metre square

Hope u got it