find the area of triangle ABC where BC=5cm, CA=7cm, angle BCA= 90°
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Answered by
37
if you want to know ,how I derive the following steps,refer the image given
angle BCA=90°
BC is the height=5cm
CA is the base=7cm
area of triangle=1/2×base×height.
=1/2×7×5 cm
=17.5 cm square
area of triangle ABC is 17.5 cm square
angle BCA=90°
BC is the height=5cm
CA is the base=7cm
area of triangle=1/2×base×height.
=1/2×7×5 cm
=17.5 cm square
area of triangle ABC is 17.5 cm square
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Anonymous:
understood?
Answered by
5
Answer:
if you want to know ,how I derive the following steps,refer the image given
angle BCA=90°
BC is the height=5cm
CA is the base=7cm
area of triangle=1/2×base×height.
=1/2×7×5 cm
=17.5 cm square
area of triangle ABC is 17.5 cm square
Step-by-step explanation:
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