Math, asked by barnalipramanick90, 1 month ago

. Find the area of triangle ABC, whose co-ordinates are A(4, -6), B(3,-2) and
C(5,2) then find the length of the median AD? ​

Attachments:

Answers

Answered by VAMSHIrajpoot521
5

Answer:

Area is 3*√20

Step-by-step explanation:

length of AD = 6units

Answered by Anonymous
17

Given :-

  • Coordinates of A = ( 4 , -6 )
  • Coordinates of B = ( 3 , -2 )
  • Coordinates of C = ( 5 , 2 )

To Find :-

  • Area of the triangle ABC

Solution :-

 \red\bigstar\: \boxed{\bf \green{Area = \frac{1}{2} \bigg[x_1(y_2 - y_3) + x_2(y_3 - y_1) +x_3(y_1 - y_2) \bigg ]}} \\

Here

  • x₁ = 4
  • x₂ = 3
  • x₃ = 5
  • y₁ = -6
  • y₂ = -2
  • y₃ = 2

Substitute values in formula

 \longmapsto \sf Area = \frac{1}{2} \bigg[4(-2-2) + 3(2 + 6) +5( - 6 + 2) \bigg ] \\

 \longmapsto \sf Area = \frac{1}{2} \bigg[4(-4) + 3(8) +5( - 4) \bigg ] \\

 \longmapsto \sf Area = \frac{1}{2} \bigg[ - 16+24 - 20\bigg ] \\

\longmapsto \sf Area = \frac{1}{2} \bigg[ - 12\bigg ] \\

\longmapsto\boxed{\sf\purple{ Area =  - 6 \:  {unit}^{2}} }\\

Similar questions