Question

Find the area of triangle ABC whose vertices are A (-5, 7), B (-4, -5) and C (4, 5).

Answer 1

Answer:

29

Step-by-step explanation:

hey guys here your answer

mark as me brainllist

Answer 2

ANSWER:-

$<font color=red>$

Area of ΔABC whose vertices are is

$(x_1,y_1),(x_2,y_2) \: and \: (x_3,y_3)are$

$Area \: of ΔABC = \frac{1}{2} [x_1(y_2,y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]$

In ΔABC, vertices are A(−5,7),B(−4,−5) and C(4,5)

$Area \: of \: triangle \: = \frac{1}{2} (- 5 (- 5 - 5 ) - 4(5 - 7) + 4(7 + 5))$

$= \frac{1}{2} ( - 50 + 8 + 48)$

$= 5 \: sq. \: units$

HOPE IT'S HELPS YOU ❣️