Find the area of triangle ABC with A (1,-4) and mid points of sides through A being (2,-1) and (0,-1)
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Answer:
A(1,-4)
Considering,
AB(2,−1)
AC(0,−1)
Let B(x
1
,y
1
)
(
2
x
1
+1
,
2
y
1
−4
)=(2,−1)
x
1
=3,y
1
=2
B(3,2)
Let C(x
2
,y
2
)
(
2
x
2
+1
,
2
y
2
−4
)=(0,−1)
x
2
=−1,y
2
=2
C(−1,2)
Area=
2
1
[x
1
(y
2
−y
3
)+x
2
(y
3
−y
1
)+x
3
(y
1
−y
2
)]
=
2
1
[3(2+4)+(−1)(−4−2)+1(2−2)]
=
2
1
[18+6+0]
=
2
24
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