find the area of triangle are AB = 3cm, BC = 6cm and AC = 4cm
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Answer:
AB=c=3cm
BC=a=6cm
AC=b=4cm
Semiperimeter = S = (a+b+c) /2 = (3+4+6)/2 = (13/2)
Area of triangle = √s(s-a)(s-b)(s-c)
area = √(13/2)((13/2)-6)((13/2)-4)((13/2)-3)
area = √(13/2)(1/2)(5/2)(7/2) = √(13*5*7)/2^4 = √455/2^4
area = (1/4)*√455 = 5.33
Hope this helps you...
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