Find the area of triangle
ASN with A(-3, -3), S(2, 1)
th A(-3, -3), S(2, 1) and N(3, 4).
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HERE'S THE ANSWER.....
IF YOU ARE IN 10th YOU SHOULD GO BY FORMULA OF AREA OF TRIANGLE:
ar(∆ASN) = ½[ X1 (y2 - y3) + X2 (y3 - y1 )+ X3 (y1 - y2)]
here,
X1 = -3 y1. = -3
X2 = 2 y2 = 1
X3 = 3 y3 = 4
PUT VALUES AND YOU WILL GET THE ANSWER.
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