Find the area of triangle BAC?
In the figure AB=6centimeter, AC=5centimeter angle BAC=90 degree CD is parallel to AB
Answers
Answered by
0
Answer:
Let ∠BAC is bisected by AD where AD touches BC at D. BC=BD+DCwhere, BC=3cm. We also have the values of adjacent sides AB=6cmand AC=5cm.
These satisfy the requirements of angle bisector theorem. Then, by the theorem, we have:
ABBD=ACDC
⇒DC=AC∗BDAB=5∗36=2.5cm
Similar questions