Math, asked by AdrijaMukherjee5494, 3 days ago

Find the area of triangle BAC?
In the figure AB=6centimeter, AC=5centimeter angle BAC=90 degree CD is parallel to AB

Answers

Answered by Aryankanani50
0

Answer:

Let ∠BAC is bisected by AD where AD touches BC at D. BC=BD+DCwhere, BC=3cm. We also have the values of adjacent sides AB=6cmand AC=5cm.

These satisfy the requirements of angle bisector theorem. Then, by the theorem, we have:

ABBD=ACDC

⇒DC=AC∗BDAB=5∗36=2.5cm

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